4[4(y+2)-(y+5)]=4(3y+1)

Solution for 4[4(y+2)-(y+5)]=4(3y+1) equation:

Simplifying
4[4(y + 2) + -1(y + 5)] = 4(3y + 1)

Reorder the terms:
4[4(2 + y) + -1(y + 5)] = 4(3y + 1)
4[(2 * 4 + y * 4) + -1(y + 5)] = 4(3y + 1)
4[(8 + 4y) + -1(y + 5)] = 4(3y + 1)

Reorder the terms:
4[8 + 4y + -1(5 + y)] = 4(3y + 1)
4[8 + 4y + (5 * -1 + y * -1)] = 4(3y + 1)
4[8 + 4y + (-5 + -1y)] = 4(3y + 1)

Reorder the terms:
4[8 + -5 + 4y + -1y] = 4(3y + 1)

Combine like terms: 8 + -5 = 3
4[3 + 4y + -1y] = 4(3y + 1)

Combine like terms: 4y + -1y = 3y
4[3 + 3y] = 4(3y + 1)
[3 * 4 + 3y * 4] = 4(3y + 1)
[12 + 12y] = 4(3y + 1)

Reorder the terms:
12 + 12y = 4(1 + 3y)
12 + 12y = (1 * 4 + 3y * 4)
12 + 12y = (4 + 12y)

Add '-12y' to each side of the equation.
12 + 12y + -12y = 4 + 12y + -12y

Combine like terms: 12y + -12y = 0
12 + 0 = 4 + 12y + -12y
12 = 4 + 12y + -12y

Combine like terms: 12y + -12y = 0
12 = 4 + 0
12 = 4

Solving
12 = 4

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.